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b:

Because $ \gamma(T)\subset\xi(U)$, there exist functions of $ T$, $ u(t)$ and $ v(t)$ such that:

$\displaystyle \forall t\in T, \gamma(t)=\xi(u(t), v(t))$

This equation's derivative in $ t$:

$\displaystyle \gamma'(t_0) = u'(t_0) \xi_u(u_0, v_0)
+ v'(t_0) \xi_v(u_0, v_0) $

where $ \xi_u=\frac{\delta\xi}{\delta u}$ and $ \xi_v=\frac{\delta\xi}{\delta v}$.



Alexis Angelidis (PhD) 2004-02-09