next up previous
Next: Second fundamental form Up: Surfaces Previous: Weingarten map

First fundamental form

The first fundamental form is the inner product restricted to tangent vectors. Let be two tangent vectors $ \vec{v},\vec{w}\in\overrightarrow{T_{x_0}S}$:

$\displaystyle \mathbb{I}(\vec{v}, \vec{w}) = \vec{v}\cdot\vec{w}$

The first fundamental form is independent from a particular surface representation, thus invariant under parameter transformation. Another point of view for a parameterised surface is to use $ 2D$ coordinates $ \vec{\tau} = (\tau_u, \tau_v)$ to describe tangent vectors. Let us note $ x_u = \frac{\delta\xi}{\delta u}(u_0,v_0)$, $ x_v =
\frac{\delta\xi}{\delta u}(u_0,v_0)$. In the basis $ (x_u, x_v)$, the first fundamental form applied to $ (\tau_u, \tau_v)$ is entirely defined by the numbers:

\begin{displaymath}\begin{array}{rclll}
E &=& x_u^2\\
F &=& x_ux_v\\
G &=& x_v^2\\
\end{array}\end{displaymath}

Thus if $ \vec{\tau}\in \overrightarrow{T_xS}$ has components $ (\tau_u, \tau_v)$ in $ (x_u, x_v)$, the first fundamental form defines a positive definite quadratic form in the tangent plane:

\begin{displaymath}\begin{array}{rcl}
\mathbb{I}(\vec{\tau},\vec{\tau})
&=& E\...
...n{array}{c} \tau_u \\ \tau_v \end{array}\!\!\right)
\end{array}\end{displaymath}

where $ E$, $ F$ and $ G$ are the first fundamental coefficients, and are not invariant under a parameter transformation. We will refer to the matrix of these coefficients as the first fundamental matrix.



Alexis Angelidis (PhD) 2004-02-09