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Normal curvature

Let $ \vec{\tau}$ be a unit tangent vector at point $ x$ of a regular surface $ S$. Then the normal curvature of $ S$ in the direction $ \vec{\tau}$ is the curvature of a normal section of $ S$ at $ x$ (a normal section is a cut plane containing the normal):

$\displaystyle \kappa(\vec{\tau}) = \mathbb{II}(\vec{\tau}, \vec{\tau})$

In the case when $ \vec\tau$ is not a unit vector:

$\displaystyle \kappa(\vec\tau_x) =\frac{\mathbb{II}(\vec\tau_x)}{\mathbb{I}(\vec\tau_x)}$



Alexis Angelidis (PhD) 2004-02-09